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2x^2-79x+57=0
a = 2; b = -79; c = +57;
Δ = b2-4ac
Δ = -792-4·2·57
Δ = 5785
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-79)-\sqrt{5785}}{2*2}=\frac{79-\sqrt{5785}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-79)+\sqrt{5785}}{2*2}=\frac{79+\sqrt{5785}}{4} $
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